One card is drawn from a well shuffled deck of 52 cards. If each outcome
is equally likely, calculate the probability that the card will be
(i) a diamond
(ii)
not an ace
(iii) a
black card (i.e., a club or, a spade)
(iv)
not a diamond
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OpenStudy (goformit100):
@perl @msingh
OpenStudy (perl):
how come your score is so high?
OpenStudy (anonymous):
exactly
OpenStudy (anonymous):
how?
OpenStudy (goformit100):
Sir Hate Probability so asking.
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OpenStudy (perl):
i) there are 13 diamonds
13/52
OpenStudy (perl):
there are 4 aces, 48/52
OpenStudy (goformit100):
Means There are 9 discs in all so the total number of possible outcomes is 9.
Let the events A, B, C be defined as
A: ‘the disc drawn is red’
B: ‘the disc drawn is yellow’
C: ‘the disc drawn is blue’
OpenStudy (perl):
what is the 9 discs?
OpenStudy (goformit100):
its the question content
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OpenStudy (perl):
can you type the whole question
OpenStudy (goformit100):
I gave there an example through which I can Analytically solve this Question