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Mathematics 16 Online
OpenStudy (goformit100):

One card is drawn from a well shuffled deck of 52 cards. If each outcome is equally likely, calculate the probability that the card will be (i) a diamond (ii) not an ace (iii) a black card (i.e., a club or, a spade) (iv) not a diamond

OpenStudy (goformit100):

@perl @msingh

OpenStudy (perl):

how come your score is so high?

OpenStudy (anonymous):

exactly

OpenStudy (anonymous):

how?

OpenStudy (goformit100):

Sir Hate Probability so asking.

OpenStudy (perl):

i) there are 13 diamonds 13/52

OpenStudy (perl):

there are 4 aces, 48/52

OpenStudy (goformit100):

Means There are 9 discs in all so the total number of possible outcomes is 9. Let the events A, B, C be defined as A: ‘the disc drawn is red’ B: ‘the disc drawn is yellow’ C: ‘the disc drawn is blue’

OpenStudy (perl):

what is the 9 discs?

OpenStudy (goformit100):

its the question content

OpenStudy (perl):

can you type the whole question

OpenStudy (goformit100):

I gave there an example through which I can Analytically solve this Question

OpenStudy (goformit100):

Thankyou @perl Sir

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