Question

an object is moving in a plane, and its position at time t is given by

x=3cos(2t)
y=4cos(3t)

a)what is the position of the particle at t=pi/4? (point P)

b) what is the velocity of the particle at t=(pi/4)

c) what is the slope of the tan line to the track of the particle at the point P (point found in part a).

I took the derivative to the x and y values set them equal to 0 but not sure what to do from there

Answer 1

Why did you set them equal to 0???

Answer 2

not sure.. bc that would give me a max/min which i dont need

Answer 3

so looking at it now. is the derivative the x,y that tells the position of the particle?

Answer 4

No.... the expressions above are parametric forms of ''displacements'' along x and y already...
For velocity you would need the derivative...

Answer 5

You getting it??? @huskerfan12 ???

Answer 6

so take the derivative of the x and y. and then ?

Answer 7

first part:)) for position just set t=pi/4 in x and y ...
Sec part))take der. of 'x' w.r.t 't' and 'y' w.r.t 't' separately and you will get components of velocity along x and y...

Answer 8

i thought for the second part you have to take the sqrt of y'^2 +x'^2?

Answer 9

and so at pi/4 the postition is (0,0)?

Answer 10

Not getting u... You won't be getting y-coordinate 0...