The area of room A is (5x^2 – 7x – 6) ft^2. Room B has an area of (8x^2 + 6x – 1) ft^2. If room A is the larger room, how much greater is the area of room A than the area of room B?
–3x^2 – x – 7
13x^2 – 13x – 7
–3x^2 – 13x – 5
3x^2 – x – 5

If you can, please explain how the problem is solved. Thank you!

Question

The area of room A is (5x^2 – 7x – 6) ft^2. Room B has an area of (8x^2 + 6x – 1) ft^2. If room A is the larger room, how much greater is the area of room A than the area of room B?  
–3x^2 – x – 7
13x^2 – 13x – 7
–3x^2 – 13x – 5
3x^2 – x – 5

If you can, please explain how the problem is solved. Thank you!

anonymous · Answer

I'm thinking the answer is the 2nd one, but i'm not sure if it is. 13x^2 - 13x - 7

reemii · Answer

You need to look at the difference. If A is greater than B, look for, compute AreaA - AreaB.
Area A - Area B = $5x^2 – 7x – 6 - (8x^2 + 6x – 1) = -3x^2-13x-5$. I'm pretty sure.

anonymous · Answer

Oh ok, ya that makes sense beacause it asked for the difference (Wow I didn't even think of that) and so you had to find difference between A & B :D Thank you!