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Can someone show the steps on how to establish this identity: 1- (sin²θ/1+cosθ) = cosθ
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\(1-\frac{\sin^2 \theta}{1+\cos \theta} = \frac{1+\cos \theta-\sin^2\theta}{1+\cos\theta}\). So, \[ \frac{1+\cos \theta-\sin^2\theta}{1+\cos\theta} = \cos \theta \] if and only if \[ 1+\cos \theta-\sin^2\theta = \cos\theta + \cos^2\theta \] it's almost done now
let's try start from left side |dw:1367107226908:dw|
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