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Use a sum identity, and the fact that 105°=60°+45°, to fine the exact value of sin 105°.
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\[\sin(\alpha +\beta)=\sin(\alpha)\cos(\beta)+\sin(\beta)\cos(\alpha)\]
yeah thats what we were using, how do i incorporate the numbers into there though?
\[\sin(45 +60)=\sin(45)\cos(60)+\sin(60)\cos(45)\]
awesome, i can simplify that on the right, thanks!
all the numbers on the right hand side should be well known\[\sin(45)=\cos(45)=\frac{\sqrt{2}}{2}\] \[\sin(60)=\frac{\sqrt{3}}{2}, \cos(60)=\frac{1}{2}\]
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