Question

Restrict the function f(x)=x^2+4x+5 so that its inverse exists.

Answer 1

make the graph

Answer 2

ohhh haha thanks

Answer 3

How would I find the inverse?

Answer 4

define it on one side of the vertex only
so first you have to find the vertex

Answer 5

first coordinate of the vertex is \(-\frac{b}{2a}=-\frac{4}{2}=-2\) so you could define your function on \(x>-2\) for example
then to find the inverse, write
\[x=y^2+4y+5\] and solve for \(y\)

Answer 6

\[-2+\sqrt{x-1}\] ?