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find (dx/dy): (2x+3y)^5=x+1
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I suggest using implicit differentiation to get dy/dx then get the reciprocal to find dx/dy.
Thank you
why not just implicit x(y)?
(2x+3y)^5=x+1 5(2x+3y)^4 (2x'+3) = x' and solve for x'
I do not see a possible way to solve for x'
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let that 5()^4 part equal say: k k(2x'+3) = x' 2kx' + 3k = x' 3k = x' - 2kx' 3k = x'(1-2k) .... and divide
Thank you!
good luck :)
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