Question

Please Help.

Answer 1

\[\frac{ 20x ^{-4} }{ 27y^2 } \div \frac{ 8x ^{-3} }{ 15y ^{-15} }\]

Answer 2

Simplify.

Answer 3

@.Sam. :) Help?

Answer 4

\[\frac{ 20x^{-4} }{ 27y ^{2} } *\frac{ 15^{y-15} }{ 8^{x-3} }\]

Answer 5

okaii i got that.

Answer 6

@Luis_Rivera Help!

Answer 7

Yo got a rule that when dividing the same variable with exponents, the exponent of the denominator is being subtracted from the exponent of the numerator. You do that here. For instance,\[\frac{ x ^{-4} }{ x ^{-3} }=x ^{-4--3}=x ^{^{-1}}=\frac{ 1 }{x }\]. You do the rest :)

Answer 8

I know the answer! I want a solution with an explanation :)

Answer 9

I got it ;D