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Good afternoon everybody... Water flows in a 420mm diameter horizontal pipe to a depth of 380mm. Calculate : A: the wetted perimeter of the pipe. B:The area of cross section of water. C:The width of the water at the surface. Any input on this badboy will be greatly appreciated.
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|dw:1367236970356:dw|
And we are to assume the water is perfectly still, perfectly horizontal, right?
This is a tough problem.
yep.the pipe is horizontal.
im as far as you at the mo.Except ive done it to scale on graph paper.
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I'm just going to brainstorm here a little. \[C=\pi d\]
|dw:1367237864003:dw| As best as I can figure, we need to figure out what theta is, because that is the only way that I can find to find the circumference of part of a circle.
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