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Mathematics 14 Online
OpenStudy (anonymous):

Good afternoon everybody... Water flows in a 420mm diameter horizontal pipe to a depth of 380mm. Calculate : A: the wetted perimeter of the pipe. B:The area of cross section of water. C:The width of the water at the surface. Any input on this badboy will be greatly appreciated.

OpenStudy (austinl):

|dw:1367236970356:dw|

OpenStudy (austinl):

And we are to assume the water is perfectly still, perfectly horizontal, right?

OpenStudy (austinl):

This is a tough problem.

OpenStudy (anonymous):

yep.the pipe is horizontal.

OpenStudy (anonymous):

im as far as you at the mo.Except ive done it to scale on graph paper.

OpenStudy (austinl):

I'm just going to brainstorm here a little. \[C=\pi d\]

OpenStudy (austinl):

|dw:1367237864003:dw| As best as I can figure, we need to figure out what theta is, because that is the only way that I can find to find the circumference of part of a circle.

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