Solve 3(x + 2) > x.
Okay... for the most part, inequalities like > and < behave like equations =. Let's get down to business. 3(x+2) > x Could you distribute that 3 over there?
yes
Then please do, and what do you get?
i dont know how to do it lol
Here, an example. 7(2x - 3) We multiply 7 to BOTH 2x and -3 7 times 2x = 14x 7 times -3 = -21 so... it becomes 7(2x - 3) = 14x - 21 Now you try, with 3(x + 2)
3(x+2) = 3x+6
Very good. So we have 3x + 6 > x Now, what do you think we do? Well, if this were an equation instead 3x + 6 = x We'd bring that x to the left side, and the 6 to the right, changing their signs in the process. Well, we can do that with inequalities like > too So 3x + 6 > x becomes...?
simple it is like 3(x+2)>x or,3x+6>x or,6>x-3x or,-2x<6 or,-x<3 or,x>-3 so we get.x>-3
not cool @sset terenz had it well in hand
It happens :) @sset please be a little more gradual in helping @and_23 did you understand every step of @sset 's solution?
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