Question

Find the sine of both angle A and angle B.

http://roads.advancedacademics.com/contentserver/content/roadssection/279559/questions/assessments/r-trigonometricratiosshortanswerquiz/geometry_8.2.11_quiz_final_2q.gif

I believe the answer is sin A = 5/12; sin B = 12/5
in a comment I'll write how I got that, could someone correct me if I am wrong? thanks!

here are the other possible answers -

A. sin A = 5/13; sin B = 12/13
B. sin A = 12/13; sin B = 5/13
C. sin A = 5/12; sin B = 12/5
D. sin A = 13/5; sin B = 13/12

Answer 1

\[\sin A = \frac{ opposite }{ hypotenuse } = \frac{ 10 }{ 24 } \div 2 = \frac{ 5 }{ 12 }\]

\[\sin B \frac{ opposite }{ hypotenuse } = \frac{ 24 }{ 10 } \div 2 = \frac{ 12 }{ 5 }\]

thanks to anyone who can help me out! :)

Answer 2

@jazzeejess The hypotenuse is always the longest side.

The length of hypotenuse is 26 cm.

Please correct it accordingly. :)

Answer 3

@luckythebest thanks for that.

So the answer would be sin A = 12/13; sin B = 5/13? Correct?

Answer 4

Just the reverse.

Sin B = 12/13 and sin A = 5/13.

Sin A= CB/AB, Sin B = AC/AB.

Answer 5

Okay, thank you so much for your help! Much appreciated!