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(4√6)/(√30) rationalizing the denominator plz show work
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\[\sqrt{30}\] multiply and divide it
Multiply and divide by \(\sqry{30}\).
Multiply and divide by \(\sqrt30}\)
Never mind..
\[\frac{4 \sqrt{6} \times \sqrt{30}}{\sqrt{30}} \implies \frac{4 \sqrt{4 \times 9 \times 5}}{30}\]
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\[\frac{ 4\sqrt{6}}{ \sqrt{30} } \times \frac{\sqrt{30} }{ \sqrt{30} }\]
\[\frac{24 \sqrt{5} }{30 }\]
\[\frac{ 4 }{\sqrt{5} }\]
how did you get 24?
\[\sqrt{9} = 3\]
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\[\sqrt{4}=2\]
(2√5 + 3√7) can you help me with this one @rajapurna
same number with - symbol
(2√5 + 3√7)^2
\[2\sqrt{5}-3\sqrt{7}\]
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to do the Square ?
so subtract then square
No you need to multiply with 2√5−3√7
(a + b)(a - b) = \[a ^{2} - b^{2}
ok thank you
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