Solve for x.

4(x + 3)^2 + 5 = 10

Question

Solve for x. 

4(x + 3)^2 + 5 = 10

e.cociuba · Answer

I need a bit help solving this problem. I'm afraid I forgot Algebra and it's been awhile since I have done it. I would appreciate some help. Thanks! :)

goformit100 · Answer

For solving this do you know the conception of : Quadratic Equations ?

e.cociuba · Answer

Ok so this is where I got so far: 

4(x + 3)^2 + 5 = 10 
                  -5     -5 
4(x + 3)^2= 5 

This is where I forgot how to do it..

e.cociuba · Answer

K got it. Thanks :)

anonymous · Answer

$$4(x+3)^2+5=10\\ (x+3)^2= \frac{10}{4}\  x+3  =   \pm \sqrt  {\frac{10}{ 4 }}\ x+3  =\frac{  \pm  \sqrt{5} }{ 2 }\\  x =  -3 \pm\frac{  \sqrt{5} }{ 2 }\\     x =  -3+\frac{\sqrt{5} }{ 2 }\  \ \  and  \ \ \ \   x =  -3-\frac{\sqrt{5} }{ 2 }\    $$