Question

find a quadratic equation with roots (4+i) and (4-i)
this is what i did and im stuck
(x-(4+i)(x-(4-i)
x^2-x(4-i)-x(4+i)-(4+i)(4-i)

Answer 1

x^2-8x+7

Answer 2

17*

Answer 3

(x-(4+i) (x-(4-i)

=> (x-4-i)(x-4+i)

So let (x-4) = a,

then (a-i)(a+i) = a^2 - i^2

we know that i = root of -1, hence i^2 = -1

and -(-1) = 1

hence the equation becomes a^2 + 1

=> (x-4)^2 + 1 = x^2-8x+16+1 = x^2-8x+17.

Hope it helped. :)

Answer 4

it really realli did help me understand better i got tht answer before bt my steps kept bothering me thank you so so so so much !!