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Find the equation of the tangent line to the curve y=6tan(x) at point (pi/4, 6)
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Using the limit definition or do you know derivatives?
I ask, because when people get tangent line questions, they may still be in the limit version. But you are using a transcendental equation so... perhaps, perhaps not. \[f'(x)=\lim_{\Delta x\to 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}.\]
here dy/dx = 6sec^2(x) put x=pi/4 u'll get slope as m=12 and u have a point (pi/4,6) so u have slope and a point i think u can get equation of tangent
use the derivative of the original equation, plug in the x value to get M Use the form (y-y1)=M(x-x1) y1 is the y cordinate i.e. 6 and x1 is the x cordinate pi/4
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