Question

Find the measure of angle P in the triangle below

http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-A09/b/assessments/R-LawofCosinesShortAnswerQuiz/Geometry_8.4.14_Quiz_FINAL_8q.gif

Answer 1

given the info you have, you'll want to use law of cosines. side c is opposite to angle C.

c^2 = a^2 + b^2 -2abcosC

we want angle P so:

48^2 = 60^2 + 36^2 -2(36)(60)cosP

solve for P :)

Answer 2

i got P = 53.1

Answer 3

\[\cos P = (RP)^2 + (PQ)^2 - (RQ)^2 / 2 (RP)(PQ) \]

That's the LAW OF COSINES :-)