Question

Solve for x in the proportion x/2x+5=-5/x
x=5
x=15
x=-25
x=-5

Answer 1

You didn't use brackets, so the fraction on the left is a little hard to read. Is this what it's suppose to look like? I just wanna make sure first :)
\[\large \frac{x}{2x+5}=-\frac{5}{x}\]

Answer 2

yea exept the 5/x is negitive @zepdrix

Answer 3

There's a negative in front of the one I wrote out, don't you see it silly?? c:

We'll start by dealing with these fractions. Getting rid of the denominators.
First, Multiply both sides by x,\[\large x\frac{x}{2x+5}=-\frac{5}{x}x\]
Notice how on the right side, we are both multiplying and dividing by an \(\large x\).
Those will cancel out for us,\[\large x\frac{x}{2x+5}=-\frac{5}{\cancel x}\cancel x \qquad \rightarrow \qquad x\frac{x}{2x+5}=-5\]We'll multiply the x's on the left side,\[\large \frac{x^2}{2x+5}=-5\]

Ok so we've successfully dealt with the denominator on the right side!
We're going to do the same for the other side.

Is this making a little bit of sense? :O
I hope

Answer 4

x = 15 is that right? @zepdrix

Answer 5

Hmm no :O Not so much

Answer 6

ok let me try again

Answer 7

x = 5? @zepdrix

Answer 8

yayy good job \c:/