Question

Can someone help me!!!

Answer 1

#7

Answer 2

(2a^2-4a+2) / (3a^2-3)
2(a^2-2a+1) / 3(a^2-1)
2(a-1)(a-1) / 3(a+1)(a-1)
2(a-1) / 3(a+1)

You can leave it at that. Or write it out as (2a-2) / (3a+3). I would just leave it factored though

Answer 3

wb 8 and 9 @dusty

Answer 4

i only saw the number 7

Answer 5

here sorry

Answer 6

im not to sure on these but @mathstudent55 do you think you could help him?

Answer 7

7. is correct. Good job @dusty

Answer 8

thank you!

Answer 9

but im not for sure on 8 & 9

Answer 10

8. (2s^2 - 5s - 12) / (2s^2 - 9s + 4)
The basic idea is the same as for 7.
First factor the numerator and denominator.

Answer 11

You need to factor
2s^2 - 5s - 12
This is a trinomial of the form
ax^2 + bx + c
To factor do the following:
1. First try to factor a common factor from all terms, if there is one.
In this case there isn't a common factor.

Answer 12

2. Multiply ac together.
In this case, a = 2, and c = -12, so ac = 2(-12) = -24

Answer 13

3. Come up with two dfactors of ac that add up to b.
In this case, we need two factors of -24 that add up to -5.
Since 8*3 = 24, -8*3 = -24, and -8 + 3 = -5, so the factors are -8 and 3.

Answer 14

4. Now break up the middle term of the trinomial, bx, into a sum of the factors from step 3.
In this case, -5s becomes -8s + 3s.
5. Rewrite the trinomial using the new broken-up middle term.
In this case, 2s^2 - 8s + 3s - 12

Answer 15

6. Now factor by parts. That means, factor a common factor out of the first two terms, and factor a common factor out of the last two terms.
In this case,
2s^2 - 8s + 3s - 12 =
2s(s - 4) + 3(s - 4)
7. Pull out the common factor to complete the factoring.
In this case,
2s(s - 4) + 3(s - 4) =
(s - 4)(2s + 3)

Answer 16

Now you need to do the same to teh denominator. You need to factor
2s^2 - 9s + 4
If you follow the steps above, youi'll get:
(2s - 1)(s - 4)

Answer 17

Now that both the numerator and the denominator are factored, you have:
(2s^2 - 5s - 12) / (2s^2 - 9s + 4) =
[ (s - 4)(2s + 3) ] / [ (2s - 1)(s - 4) ]
Notice that s - 4 is in both the numerator and denominator, so you can divide both the numerator and denominator by s - 4:
(2s + 3) / (2s - 1)

Answer 18

That's the final answer of 8.
For 9, you once again have to factor the numerator and denominator if possible. This happens to be a very simple problem of this type because the factoring involved is very easy.