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Mathematics 14 Online
OpenStudy (anonymous):

today

OpenStudy (anonymous):

Find the value of x. If necessary, round your answer to the nearest tenth. The figure is not drawn to scale 21.9 181.3 24 13.5

OpenStudy (jdoe0001):

can you get it from there?

OpenStudy (anonymous):

no sorry hun confused

OpenStudy (jdoe0001):

what do you think the RED leg/side value is?

OpenStudy (anonymous):

i dont know how to find that

OpenStudy (jdoe0001):

look at the graphic, the "7" long line is a Bisector, so is half to the left, and half to the right, so the RED line is half 23

OpenStudy (anonymous):

11 1/5

OpenStudy (jdoe0001):

yes

OpenStudy (jdoe0001):

is a right angle, one is 90degrees, so, use the pythagorean theorem to get the BLUE line, or Hypothenuse

OpenStudy (anonymous):

how

OpenStudy (jdoe0001):

what did you get for the blue line? :)

OpenStudy (anonymous):

7 squared + 23 squared = c squared >

OpenStudy (jdoe0001):

bear in mind that, \( c^2=a^2+b^2 \implies c=\sqrt{a^2+b^2} \)

OpenStudy (jdoe0001):

and as you can see, the leg/side for THAT triangle, is the radius of the circle, which is the same for any angle, and thus THAT BLUE leg/side, is the same value of "x"

OpenStudy (anonymous):

im felling my brain is overwhelmed

OpenStudy (jdoe0001):

all this I'd gather is in your textbook :)

OpenStudy (anonymous):

I really need this done toay along with others , like i have tofinish in less than a omonth

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