Question

how do you factor the trinomial, please explain (ex: x^2 +8x+7

Answer 1

( x+7) (x+1)

Answer 2

therefore x+7 =0 , where X= -7 and x+1 = 0, where x = -1

Answer 3

the "how" might help you factor others tho ..... since of course they dont ALL factor into (x+7) and (x+1)

Answer 4

if a trinomial is going to factor out, it will take the form:

(px+q)(mx+n) ; expanding this out we get

pm x^2 + pnx + qm x + qn

pm x^2 + (pn +qm) x + qn

we can use this to compare your example with by equating coefficients

pm x^2 + (pn +qm) x + qn = x^2 +8x+7

pm = 1
pn+qn = 8
qn = 7

Answer 5

when the example has 1 as a leading coeff, we can let p=m=1, which simplifies this to

n+q = 8
qn = 7

so we are looking for factors of 7, that add up to 8

7(1) = 7, 7+1 = 8 those fit