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i need calc help A particle is moving with acceleration a(t)=36t+2. its position at time t=0 is s(0)=10 and its velocity at time t=0 is v(0)=12. What is its position at time t=6?
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integrate a(t) ?
so that would be a(t) = 18t^2+2x
if you integrate acceleration you get velocity
v(t) = 18t^2+2t + constant
So then i would plug in 0 into x and solve for c giving me the value of 12?
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yes
if you integrate velocity you get position
so 6s^3+t^2+12x+c then i plug in 0 to give me c = 10 so... 6s^3+t^2+12t+10 = position?
awesome i got it. thanks!
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