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Mathematics 8 Online
OpenStudy (anonymous):

Can someone help me with vectors? Will post picture on comments

OpenStudy (anonymous):

OpenStudy (inkyvoyd):

I'd help you, but that picture is small and sideways.

OpenStudy (anonymous):

@inkyvoyd

OpenStudy (anonymous):

a. The floor of the attic is along the xy-plane. How far will the peak of the roof be above this floor? How can you tell? b. How long and how wide will the house be?

OpenStudy (inkyvoyd):

Damnit, you caught me. @jim_thompson5910 please help her? Thank you :)

jimthompson5910 (jim_thompson5910):

the z component of the vector v is 8 so the peak is 8 ft away from the floor of the attic

jimthompson5910 (jim_thompson5910):

the x and y components of the vector h are: 20 and 45 so the width of the house is 20 ft and the length of the house is 45 ft

OpenStudy (anonymous):

Okay. I see. It also asks me how long to make the rafter that goes from the corner with the marked angle to the peak of the roof along the slanted ridge. How long will this rafter be? What would i have to do?

OpenStudy (anonymous):

@jim_thompson5910 what is the rafter?

jimthompson5910 (jim_thompson5910):

find the length of vector v

OpenStudy (anonymous):

by doing magnitude?

jimthompson5910 (jim_thompson5910):

use the formula |v| = sqrt(x^2 + y^2 + z^2)

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (anonymous):

and that would be the rafter?

jimthompson5910 (jim_thompson5910):

length of it yes

OpenStudy (anonymous):

so what does the angle have to do with it?

jimthompson5910 (jim_thompson5910):

not exactly sure, maybe that's for a different problem

jimthompson5910 (jim_thompson5910):

it's not asking anything about the angle at the moment

OpenStudy (anonymous):

I see. It is asking me about roof tiles that will lie above the rafter and that they will have to be cut at an angle. Is that angle the one shown?

jimthompson5910 (jim_thompson5910):

possibly, but I'm having trouble visualizing how they would be placed exactly

OpenStudy (anonymous):

in the picture it shows an angle in the corner. would that be it?

jimthompson5910 (jim_thompson5910):

I think so, but I'm not 100% sure about that part

jimthompson5910 (jim_thompson5910):

if they want that angle though, you first need to find the vector z = v - h then you find the angle of that vector

OpenStudy (anonymous):

angle of vector z?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

is there an equation?

jimthompson5910 (jim_thompson5910):

I guess if you really want to be technical, you want the angle between the vector z and the vector w where w = < 20, 0, 0 >

jimthompson5910 (jim_thompson5910):

If you want to find the angle between vectors u and v, then theta = arccos[ (u dot v)/(|u|*|v|) ] where u dot v = dot product of vectors u and v |u| = length of vector u |v| = length of vector v

jimthompson5910 (jim_thompson5910):

sorry I should make the clarification the vector w is really w = <-20, 0, 0>

OpenStudy (anonymous):

and vector u and v would be w and z?

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (anonymous):

z would be <-10,-10,8>?

jimthompson5910 (jim_thompson5910):

let me double check

jimthompson5910 (jim_thompson5910):

I'm getting the same

jimthompson5910 (jim_thompson5910):

so yes, z = < -10, -10, 8>

OpenStudy (anonymous):

okay i see! thank you!

jimthompson5910 (jim_thompson5910):

you're welcome

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