Question

Please help...
Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at y = ± 5/6x

Answer 1

I see the center is (0,0). Do you see that?

Answer 2

yes but how does that fit in the equation?

Answer 3

\[\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1 \]

Answer 4

Center is (h,k). That is the equation of a hyperbola with horizontal transverse axis. Is the transverse axis of your hyperbols horizontal?