Question

q^2+3q-54=(q-6)(q+[ ]) FIND: [ ] n^2+5n-50=(n+5)(n-[ ]) FIND: [ ] please :) thanks!

Answer 1

\[q^2 +3q-54=(q-6)(q+[x])\]
\[n^2 + 5n -50 = (n+5)(n-[x])\]
In both instances you are factoring.

Answer 2

In the first one, how would you factor the left side?

Answer 3

What multiplied by 6 gives you negative 54, and when added gives you positive 3?

Answer 4

negative 6, excuse me

Answer 5

9!

Answer 6

ahh thank you

Answer 7

Right, sorry I got distracted.
So, what would the answer to the second one be?

Answer 8

-10 :)

Answer 9

Well, because there is a negative sign already there, it should just be x=10