Question

What is the solution of the system? Use substitution.

x = –2y + 10
–6y = 6x – 6
z = –3x + 10y

A. x = 9, y = –8, z = 114
B. x = –8, y = 9, z = 114
C. x = –8, y = 114, z = 9
D. x = 114, y = 9, z = –8

Answer 1

@.Sam.

Answer 2

When x = –2y + 10 ,
From
–6y = 6x – 6
–6y = 6( –2y + 10 ) – 6
Solve for y

Answer 3

? I such at this

Answer 4

so its C

Answer 5

\[–6y = 6( –2y + 10 ) – 6 \\ \\ -6y=-12y+60-6 \\ \\ 6y=54 \\ \\ y=9\]
Get it?

Answer 6

no

Answer 7

You distribute 6 into brackets
\[–6y = 6( –2y + 10 ) – 6\]
\[-6y=-12y+60-6\]
Add 12y to both sides,
6y=54
Divide both sides by 6
y=9

Answer 8

both sides of what

Answer 9

I don't understand this at all and slopes forget it