Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (ladiesman217):

medals & fans rewarded

OpenStudy (ladiesman217):

\[x ^{2}-4x=5\]

OpenStudy (ajprincess):

\(x^2-4x=5\) \(x^2-4x-5=\) use quadratic formula to find x.

OpenStudy (compassionate):

Korra stahp. Itachi is at work.

OpenStudy (ajprincess):

who is itachi @compassionate?

OpenStudy (compassionate):

\[ \begin{array}l\color{red}{\text{D}}\color{orange}{\text{O}}\color{#E6E600}{\text{ }}\color{green}{\text{Y}}\color{blue}{\text{O}}\color{purple}{\text{U}}\color{purple}{\text{ }}\color{red}{\text{E}}\color{orange}{\text{V}}\color{#E6E600}{\text{E}}\color{green}{\text{N}}\color{blue}{\text{ }}\color{purple}{\text{A}}\color{purple}{\text{N}}\color{red}{\text{I}}\color{orange}{\text{M}}\color{#E6E600}{\text{E}}\color{green}{\text{?}}\color{blue}{\text{}}\end{array} \]

OpenStudy (austinl):

\[x=\frac{-b \pm \sqrt{b^2-4 a c}}{2a}\]

OpenStudy (ajprincess):

the values of a, b nd c can be found by comparing the equation \(x^2-4x-5=0\) with the general equation \(ax^2+bx+c=0\). Does that help? @ladiesman217

OpenStudy (ladiesman217):

ok thnx

OpenStudy (ladiesman217):

so x=-1 & x=5

OpenStudy (ajprincess):

plz check the signs:)

OpenStudy (ladiesman217):

aren't those the correct signs

OpenStudy (ajprincess):

nope:(

OpenStudy (ajprincess):

what are the values of a, b and c?

OpenStudy (ladiesman217):

\[-1^{2}-4*(-1)=5\]

OpenStudy (ajprincess):

oops reallly soorrry.u r 100% right:)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!