Given that y=3x^2+6x-7/(x+1)^2
Show that dy/dx = 20/(x+1)^3

Question

Given that y=3x^2+6x-7/(x+1)^2
Show that dy/dx = 20/(x+1)^3

anonymous · Answer

take long division, you get y = $$y = 3-\frac{ 10 }{ (x+1)^2 }$$ then take derivative, the sum, first term =0, second term = LHS of yours

anonymous · Answer

Thanks that helped a lot, but is there anyway to use the product rule for the denominator then the quotient rule for the rest. I tried and it didn't work. I think I would find this way much easier though.

anonymous · Answer

sorry for blur , I don't pay attention until I check, but it doesn't matter,

anonymous · Answer

You made it look so easy, finally understand it now. 
Thanks for the help it is much appreciated