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Mathematics 8 Online
OpenStudy (anonymous):

I need help with a couple of math problems... Can anyone help? I have trouble with these!! http://curriculum.kcdistancelearning.com/courses/ALG1x-HS-A06/b/Exams/9HW2/9HW2_q1.gif

OpenStudy (nubeer):

\[\frac{ x+2 }{(x+2)(x-2) }\]

OpenStudy (nubeer):

factorising denominator.. now u can cancel the x+2 part.

OpenStudy (anonymous):

How do I do that? I really have a lot of trouble with these!!

OpenStudy (nubeer):

hmm do what? factors or cancelation/?

OpenStudy (anonymous):

Cancelation..

OpenStudy (nubeer):

you have to see wht part is same in numerator and denominator both

OpenStudy (anonymous):

x+2 are the same...

OpenStudy (nubeer):

yes so u can cancel the one in numerator and denominator.

OpenStudy (anonymous):

Then whats left is x-2

OpenStudy (nubeer):

yes.. so that remainting part would be your answer

OpenStudy (anonymous):

-2?

OpenStudy (nubeer):

no.. :( remainging part.. whole of it. \[\frac{ 1 }{x-2 }\]

OpenStudy (anonymous):

But, the answers are a. 2 b. -2 c. 2 and -2 d. no exclusions

OpenStudy (nubeer):

well what was the complete question :/

OpenStudy (anonymous):

What number(s) should be excluded as values of x in the polynomial?

OpenStudy (nubeer):

2

OpenStudy (anonymous):

Ok... I have a couple more I need help with...

OpenStudy (nubeer):

lol how many.

OpenStudy (anonymous):

8 :o ... lol

OpenStudy (nubeer):

lol thts alot. :P

OpenStudy (anonymous):

I Know... These are hard for me :/

OpenStudy (nubeer):

lol i see.. so u want my help with all of them?

OpenStudy (anonymous):

Please?

OpenStudy (anonymous):

?

OpenStudy (nubeer):

lol umm.. yeah maybe :P

OpenStudy (anonymous):

Ok.....

OpenStudy (nubeer):

ok u can post here but lol if u promise me soemthing. :P

OpenStudy (anonymous):

Multiply and simplify

OpenStudy (anonymous):

What's the promise?

OpenStudy (nubeer):

lol u gonna write a testimonial for me . :P

OpenStudy (anonymous):

Ok... How do I do that?

OpenStudy (nubeer):

lol.. its like going in my profile and see testimonial and u might see some option there ..lol u can try fgure out i will do ur question

OpenStudy (anonymous):

Ok :)

OpenStudy (nubeer):

\[\frac{ x+3 }{ x } \times \frac{ x+4 }{ (x+4)(x+3) }\] now u can cancel out the one u can. :)

OpenStudy (nubeer):

and i think u might have to fan me first before writing it. :P

OpenStudy (anonymous):

I am not suppose to fan you?

OpenStudy (nubeer):

why not?

OpenStudy (anonymous):

I am still confused on how to get there to get to the testnimal

OpenStudy (nubeer):

lol. sorry.. its ok.. lets just focus on ur question :)

OpenStudy (anonymous):

You sure? I want to write it now lol!

OpenStudy (nubeer):

lol its ur choice if u want but lets keep doing problems too.

OpenStudy (anonymous):

Ok... So where are we at?

OpenStudy (nubeer):

i just wrote above how to do it

OpenStudy (anonymous):

Ok... I wrote the testinomail!!

OpenStudy (nubeer):

lol i saw.. thats sweet of u.. <3

OpenStudy (anonymous):

No problem!! Haha... So this is what was wrote up there \[\frac{ x+3 }{ x } \times \frac{ x+4 }{ (x+4)(x+3) }\]

OpenStudy (nubeer):

yeah so u can stact cancelling.. :)

OpenStudy (anonymous):

Idk... It's messed up on my computer....

OpenStudy (nubeer):

lol x+4 can be cancelled as both are numerator and denominator..

OpenStudy (anonymous):

Yes... Then there is x+3?

OpenStudy (nubeer):

yes exactly u have to cancel that too.. lol u getting the hang of it nwo. :)

OpenStudy (anonymous):

Yes... haha ... The answer will be 3? Right

OpenStudy (nubeer):

nooo.. how u got 3 nw? :(

OpenStudy (anonymous):

Idk ... Now I am lost!!

OpenStudy (anonymous):

@nubeer

OpenStudy (nubeer):

show me what u r left with after cacenlation.

OpenStudy (anonymous):

I don't know .. Can you put the exation out again?

OpenStudy (nubeer):

hmm u have to cancel out an expression which is same in numerator and denominator BOTH

OpenStudy (anonymous):

I don't know and I am getting a headache lol ... But, can we move to an easier problem?

OpenStudy (nubeer):

lol ok ur choice.. :P

OpenStudy (anonymous):

What is the least common multiple, LCM, of the two monomials? 15x2y3 and 18xy2

OpenStudy (nubeer):

3xy^2

OpenStudy (anonymous):

What is the least common multiple, LCM, of the two polynomials? (x + 3) and (x2 - 9)

OpenStudy (nubeer):

(x+3)

OpenStudy (nubeer):

\[\frac{ 4a+8+3a+6 }{ 12 }\] just solve this.

OpenStudy (anonymous):

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