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Mathematics 16 Online
OpenStudy (anonymous):

What is the length of the hypotenuse of the triangle below? A. 1 B. 10 sqrt 2 C. 5 sqrt 2 D. 5 E. 25 sqrt 2 F. 10

OpenStudy (anonymous):

OpenStudy (anonymous):

use pythagoras theorem which says: \[H^2=O^2+A^2\]

OpenStudy (anonymous):

H=Hypotenuse O=Opposite A=Adjacent

OpenStudy (anonymous):

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OpenStudy (anonymous):

how do i square root 5^2

OpenStudy (anonymous):

Take the square root of 2 Multiply that by 5 That's the length of 1 side Take that length and square it. Since both sides are the same length, then double that answer (same thing as s1^2 + s2^2) h (the hypotenuse) is the square root of that number.

OpenStudy (anonymous):

confused

OpenStudy (anonymous):

What is it that's confusing you?

OpenStudy (anonymous):

\[H^2= (5\sqrt2)^2+ (5\sqrt2)^2\] \[H^2=100\] hope you can continue from there....

OpenStudy (anonymous):

it came out to be 20

OpenStudy (anonymous):

you took the sqrt of 100 and you got 20??

OpenStudy (anonymous):

10 sqrt 2?

OpenStudy (anonymous):

Stop guessing. What's the square root of 100?

OpenStudy (anonymous):

do you use a calculator??

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