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Mathematics 21 Online
OpenStudy (anonymous):

How do you find the volume of a rectangular box given only the height and width? The height is 25 units and the width is 15 units.

OpenStudy (anonymous):

do you have the final volume?

OpenStudy (anonymous):

no that was all they gave me

OpenStudy (anonymous):

the diagram showed a rectangular cube with an elipse on the top and bottom and told me to find the volum when the width is 15 and height is 25

OpenStudy (anonymous):

Can't be done. You have to have 3 measurements to find volume. There has to be more information available.

OpenStudy (anonymous):

I thought it was impossible... but maybe the elipse has something to do with it?

OpenStudy (anonymous):

Only if the ellipse had its formula AND occupied the box's length.

OpenStudy (anonymous):

well it doesnt have a fomula but it seems to be the box's length, at least im guessing its meaning too

OpenStudy (anonymous):

Ellipses are rather mathematically complicated - especially compared to circles. Definitely NEED a formula for it if its presence defines the length of the box. Here's a little about ellipses: http://www.clausentech.com/lchs/dclausen/algebra2/ellipses.htm

OpenStudy (anonymous):

so is this question solvable? because im still trying

OpenStudy (jdoe0001):

maybe by 'volume' they meant 2D volume, rather than 3D :|

OpenStudy (anonymous):

lol na the answers given are 12046, 4447,5625,4418,1207. The only possibility is they left information out which i doubt

OpenStudy (anonymous):

Not by me, and I don't believe in magic. :-) The best you can do is find the area of the frontface and backface with H*W

OpenStudy (anonymous):

ok thanks for trying though. im trying to use trig functions to solve it by expanding out the cube

OpenStudy (anonymous):

WHY DIDN'T YOU SAY THAT???? They are all you need to figure out the width!!!

OpenStudy (anonymous):

Hold on...

OpenStudy (jdoe0001):

what is the "verbatim" question?

OpenStudy (anonymous):

Determine the volume of the solid figure below.

OpenStudy (jdoe0001):

something tells me we're getting shortchanged in the transcription :P

OpenStudy (jdoe0001):

"Determine the volume of the solid figure below" , ok, let's see the "figure below" :)

OpenStudy (anonymous):

um... could you draw it out? its a rectangular cube with a height of 25, width of 15 and two elipses, one on the top plane and one on the bottom plane and thats it

OpenStudy (jdoe0001):

is it on paper? if it's on the screen just take a screenshot and attach it :|

OpenStudy (anonymous):

its on paper

OpenStudy (jdoe0001):

any digicam around? :), I mean, most cellphones have one

OpenStudy (jdoe0001):

or a webcam

OpenStudy (anonymous):

Here's what I think this all means: These numbers are WAY to large to be "lengths" of this box. I think they're the volumes, and you're supposed to extrapolate the length from it. Height*width = 25*15=375 This means volume / 375 = length So if volume is the first figure, then length must be the second one. 12046 = 32.12266666 4447 = 11.858666666 5625 = 15 4418 = 11.781333333 1207 = 3.2186666666 Take your pick. I think I see the probable answer.

OpenStudy (anonymous):

im not sure where your getting at. I mean i understand the whole process but im not sure what you mean by the probable answer.

OpenStudy (anonymous):

I'm only picking the integer quotient because it's a nice and pretty integer value, just like the H and W are.

OpenStudy (anonymous):

ah well then that would make sense lol but thats not the right one :/ do you want to know the right answer?

OpenStudy (anonymous):

Yes, DEFINITELY.

OpenStudy (anonymous):

it was D) 4418 lol im really not sure how though

OpenStudy (anonymous):

Which would make the length = 11.781333333 That number has GOT to have been made available to you somewhere. H=25 W=15 L = 11.781333333 Volume = H*W*L 25 * 15 * 11.781333333 = 4417.999999875 = 4418 That just doesn't make any sense to me Even if you fractionalized 11.781333333 you get 11 25/32, which is ridiculous. Tell your teacher qweqwe said she's nuts. :P

OpenStudy (anonymous):

haha ok i wll and thanks for the help. I think im going to keep trying at this. You never know i may get lucky in the next ten years or so....

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