the equation of the vertical asymptote of f(x)= 2/2x+9 ?
it's either x= 4.5 x= -4.5 x=9 or x= -9
vertical asymptote -> value of "x" for which "y" becomes infinite or undefined this happens when the denominator becomes "0"
when you set the denominator to "0" and solve for "x", what do you get?
9
what is the denominator?
9
the bottom part of a fraction is called the denominaor
so, what is the denominator of \[ y={2\over 2x+9} \]
the bottom part says 2x+9
good. that is your denominator. now, we set it to "0" and solve for "x"
x would be -4.5 right?
bingo
ayeee lol aww thank you!
what this means is that, when x=-4.5, you cannot solve for y try it :)
y would be 2/0
and can you divide something by 0?try with the calculator
noo wont work
yes. so, that is the vertical "asymptote" f(x) cannot have a value for x=-4.5 since x=a number is a vertical line, hence the name
okay , i understand it better now
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