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Mathematics 16 Online
OpenStudy (anonymous):

the equation of the vertical asymptote of f(x)= 2/2x+9 ?

OpenStudy (anonymous):

it's either x= 4.5 x= -4.5 x=9 or x= -9

OpenStudy (anonymous):

vertical asymptote -> value of "x" for which "y" becomes infinite or undefined this happens when the denominator becomes "0"

OpenStudy (anonymous):

when you set the denominator to "0" and solve for "x", what do you get?

OpenStudy (anonymous):

9

OpenStudy (anonymous):

what is the denominator?

OpenStudy (anonymous):

9

OpenStudy (anonymous):

the bottom part of a fraction is called the denominaor

OpenStudy (anonymous):

so, what is the denominator of \[ y={2\over 2x+9} \]

OpenStudy (anonymous):

the bottom part says 2x+9

OpenStudy (anonymous):

good. that is your denominator. now, we set it to "0" and solve for "x"

OpenStudy (anonymous):

x would be -4.5 right?

OpenStudy (anonymous):

bingo

OpenStudy (anonymous):

ayeee lol aww thank you!

OpenStudy (anonymous):

what this means is that, when x=-4.5, you cannot solve for y try it :)

OpenStudy (anonymous):

y would be 2/0

OpenStudy (anonymous):

and can you divide something by 0?try with the calculator

OpenStudy (anonymous):

noo wont work

OpenStudy (anonymous):

yes. so, that is the vertical "asymptote" f(x) cannot have a value for x=-4.5 since x=a number is a vertical line, hence the name

OpenStudy (anonymous):

okay , i understand it better now

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