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Simplify, please help! a.logc C^y b.N^logy Q c.log(xy) d.log X^r e.log m/n
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Is log(xy)= logx+logy? And is log m/n= logm-logn?
can you draw b please?
|dw:1367591910230:dw|
Also is a, \[\log_{c} C^y\]?
Yes.
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Two seconds
Your idea for c&e are correct so use them for d: \[logx^r=rlogx\] for a: \[\log_{c} C^y=y \log_{c}C \] As for b, I am sorry but I have no idea but I'll leave you some links to help you
http://www.mathwords.com/l/logarithm_rules.htm http://www.wolframalpha.com/input/?i=Q*N%5Elog%28y%29
Would D be r log x
It should be. Then again it had been a while since I did logarithms so use the mathwords website and that will give you the rule
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