Question

A point in space has the coordinates (7,-3,8). How far is the point from the x-axis?

Answer 1

how do you have 3 coordinates?

Answer 2

xyz plane

Answer 3

oh duuh. lol

Answer 4

Sorry I just wrote a load of rubbish. To do this you need to use trigonometry, as the point (7,0,0) is on the x axis you can disregard the x point. To find the distance you equate:
\[Distance=\sqrt{(-3)^2+8^2}\]
This will give you a distance of \[\sqrt(73)\] or 8.54

Answer 5

thats what i got but apperently the answer sheet disagrees. It says the answer is 11

Answer 6

I can personally guarantee that is wrong. Maybe the question is phrased differently. Does it say something like:

You travel 7 spaces in the x direction, 3 spaces back in the y direction and 8 in the z direction. how far would you need to travel along these lines to get back to the x axis?

Because otherwise, itd be trigonometry. Alternatively if this is a vector-scalar question, that could affect the answer

Answer 7

no i refraised the question word by word. And i will take your word for it cause i got the same answer lol thanks

Answer 8

If you want you can post the exact question and I can try to work out what they are asking?

Answer 9

i did post the exact question. Word by word the question was "A point in space has the coordinates (7,-3,8). How far is the point from the x-axis?"

Answer 10

Apologies, yeah I would just stick with it. They can't mark you wrong

Answer 11

ok thanks