Question

P(6 2)
how do you evaluate this?
help please!!

Answer 1

P(6 2)?

Answer 2

PERMUTATIONS
Yes, P(6,2)

Answer 3

\[P=\frac{n!}{(n-k)!}\]

Answer 4

Using 6 and 2,
\[P=\frac{6!}{(6-2)!}\]

Answer 5

Are you familiar with factorials?

Answer 6

yes.

Answer 7

So what do you get?

Answer 8

6 factorial means
\[6!=6 \times 5 \times 4 \times 3 \times 2 \times 1\]

Answer 9

i did the equation and i get 180, what am i doing wrong?

Answer 10

12
30
360
these are the answer choices.

Answer 11

I'm not sure but
\[\frac{6!}{(6-2)!}=\frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{4!}=\frac{6 \times 5 \times \cancel{4 \times 3 \times 2 \times 1}}{\cancel{4 \times 3 \times 2 \times 1}}=6 \times 5=30\]

Answer 12

Do you get it now?

Answer 13

yes, thank you! :D