Question

Brennan is making a poster for the drama club’s new production. It is a regular pentagon with side lengths of 12 inches. The school wants to put up a giant replica of the poster during athletic events.

If the length of each side is 8 times the original, how many times larger is the area of the replica than the area of the original?

Answer 1

Im working on the math right now for this problem.

Answer 2

@drizzy333 okay thank you :D

Answer 3

welcome

Answer 4

I know that the area of the original pentagon is 247.75

Answer 5

@drizzy333 how did you get that ?

Answer 6

You have to do cut the pentagon up into equal triangles, therfore there would be 10 triangles. You make the short side of each triangle 1/2 of the original pentagons length, so in this case it would be 6.

Answer 7

Visual Aid for what I just wrote. Once you have done that you just find the area of one triangle and you multiply by 10. to get the area of the Pentagon

Answer 8

For the larger pentagon's area, you would have to multiply 12 and 8 because the larger penatagons sides are 8 times the first. Therfore the lenght of the larger penatgons sides are 98 inches. Divide that by 2 to get the length of each triangle. Which means that the side of the triangle is 48 inches.
Find the areao of one triangle multiply by 10 and you get 15,855.92 as the area of the larger pentagon.

Answer 9

Finally, you have to see how many times larger the 2nd pentagon is when compared to the original. So you do 15,855.92 / 247.75 and you get... that the 2nd pentagon is approcimately 64 times larger. The answer is

Answer 10

Just incase you didnt understand that , this website should help www.math-prof.com/Geom/Geom_Ch_26.asp

Answer 11

Sorry for making that so Complicated.

Answer 12

@drizzy333 lol its okay but thank you for the help :D

Answer 13

So simply, the answer is approximately 64

Answer 14

Welcome, I sent you a message by the way.

Answer 15

Thank you.