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evaluate the expression e^ln15
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In general e^(ln(x)) = x and ln(e^x) = x
im confused..
basically the e^x and ln(x) functions undo each other and cancel each other out
so e^(ln(2)) = 2 for example
because the ln(2) gives you some number if you plug this result into e^x, then you'll get 2 back again because the two cancel each other out
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so basically the answers 15 .. jut whatever is right ?
yep e^(ln(15)) = 15
whatever a is** thanks
yw
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