Question

need help for two factoring questions:
1) x^3+19x+60,
and
2) x^2-19x+48

Answer 1

@karatechopper help me please?? and hey! long time no see!

Answer 2

hmm..
bottom one..
( x-3) x-16)

Answer 3

Sorry I meant,
(x-3)(x-16)

Answer 4

Find the factors of 48 that subtract to make 19

Answer 5

*-19

Answer 6

also, how do you \[\sqrt{48}\] without a calculator?

Answer 7

you estimate

Answer 8

48 is closer to 49 and Sqrt of 49 is 7 so sqrt of 48 is approximately 7

Answer 9

>.< i need exact answers. and i need to show work.

Answer 10

well, what are the factors of 48?

Answer 11

1,48
2,24
3,16
4,12

Answer 12

Now, which one of these factor pairs have a number that has a square root?
3,16
and
4,12

Answer 13

Lets try 4,12
the square root of 4 is two. So that goes outside the radical.
Making the radical become..
\[2\sqrt{12}\]

but we notice that the 12 can still be reduced. So we know that that factor pair does not work.

Answer 14

Lets try 3,16
Whats the square root of 16? >>4.
So 4 would be outside the radical..making it look like this:
\[4\sqrt{3}\]

Answer 15

we notice that that radical can't be reduced more...
THEREFORE..
\[\sqrt{48}=4\sqrt{3}\]