How to get the area of semicircle attached to triangle if your radius is 4 and the hight of triangle is 6?
|dw:1367686851652:dw| You know the area of a circle is \[A=\pi \times r^{2}\] and this is half of a circle, so you have \[A=\frac{1}{2}(\pi \times r^{2})\]
A = 1/2(3.14)(4.4) = 25.12
That's for A of semi circle... In triangle, do I use the 16 for the base of triangle?
How can I get the Area of triangle?
How can I get the base of triangle?
From the radius of semi circle?
Are you looking for the area of the semicircle AND the area of the triangle like this? |dw:1367688494052:dw|
Yes
If so, then The area of the half-circle was correctly described by eSpeX: 1/2 pi*r^2 The area of the triangle is 1/2*B*H H=6 B=2r
I got the area of semi circle I just need to get the area of triangle so I can add A of SC Nd T...
Okay, and... The area of the triangle is 1/2*B*H H=6 B=2r
The radius of haft circle is 4
Yes. I think we've got that pretty much nailed down. :-)
So T = 1/2(bh) = 1/2 (4.4)(6) ? Like that?
Yes. Just like that, as long as by "(4.4)" you men (4 PLUS 4)
I should (4+4) not x?
I mean add it?
Yes. Because the radius is HALF THE WIDTH of the circle, and the base of the triangle is the ENTIRE WIDTH of the circle. This means that the base is equal to 2r, and 2r is the same as r plus r.
Ok thanks.... Got it....
So what's your answer? :-)
24
Am I right?
Correct! That's the area of the triangle. Excellent! And what did you get for the area of the semicircle?
So 25.12 + 24 = 49.12
I got 25.13272, but 25.12 may be due to rounding errors. I would call it "correct"! :-) My math is: r=4 r^2 = 16 pi = 3.14159 p*r^2 = 3.14159*16 = 50.26544 half that (since we're talking SEMIcircle) is 25.13272
Hehe... Super thanks....
PS: I just redid my math using 3.14 and I got your 25.12 So since most teachers accept 3.14 for the purpose of calculating pi, then you're good to go!! Glad I could help!! :-)
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