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Mathematics 15 Online
OpenStudy (anonymous):

sinx = √3cosx solve

OpenStudy (anonymous):

start with looking at a unit circle for sin and cos

OpenStudy (anonymous):

how do u know if there is more tan one answer

OpenStudy (anonymous):

*than

OpenStudy (anonymous):

looking at the unit circle, you can tell when a value will be negative or positive

OpenStudy (anonymous):

sinx/cosx=\[\sqrt{3}\] tanx=\[\sqrt{3}\] x=\[\pi\]/3 or 60 degrees

OpenStudy (anonymous):

i understand that part...the answer i got is tanx = pi/3 but its also 5pi/3

OpenStudy (anonymous):

tan(pi/3) and tan(5pi/3) are the same

OpenStudy (anonymous):

yes there'll be many pi/3 s you gotta tell the domain of x

OpenStudy (anonymous):

do u have to list all of them?

OpenStudy (anonymous):

there would be an infinite amount

OpenStudy (anonymous):

o alright...in the lectue notes that i was reading for my class it says to subtract the answer from 2pi to get the other values

OpenStudy (anonymous):

it works sometimes but not all the time

OpenStudy (anonymous):

\[\sin x=\sqrt{3}\cos x\] \[\frac{ \sin x }{ \cos x }=\sqrt{3}\] \[\tan x=\sqrt{3}=\tan 60,\tan \left( 180+60 \right)\] \[x=60,240\]

OpenStudy (anonymous):

in these kind of problems the domain of x is provided check the ques once again

OpenStudy (anonymous):

ok thank u for the help

OpenStudy (anonymous):

ooo ok now i see what your explaining the range they give is from o to 2pi

OpenStudy (anonymous):

thanks again

OpenStudy (anonymous):

in 0 to2 pi only two solutions 60,240 i.e pi/3, pi+pi/3

OpenStudy (anonymous):

yes

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