The length of a diagonal of a square is 5 inches. Find the perimeter of the square

Question

anonymous · Answer

Do you have the area of the square?

anonymous · Answer

Thats all the info I have

anonymous · Answer

This URL can help you out for sure http://www.algebra.com/algebra/homework/word/geometry/Geometry_Word_Problems.faq.question.131017.html

anonymous · Answer

This is the correct answer:
To find the perimeter you have to find the length of the sides. Since it is a square, all the sides are equal. The diagonal=5. That divides the square in two right triangles. |dw:1367726793626:dw|
By the Pythagorean theorem I get that $$a^2+b^2=c^2$$ so c=5, a=x , and b=x therefore $$5^=x^2+x^2\rightarrow5=2x^2\rightarrow2.5=x^2\rightarrow x=1.58$$so the perimeter would be 4x=6.325 inches

Hope I helped, lemme know by giving me a medal!

anonymous · Answer

6.325 is incorrect.

Pytjagoras sez that the square of the hypotenuse equals the sum of the squares of the sides.
So "x" would be:
sqrt((5^2)/2)

The perimeter is then 4x

anonymous · Answer

12.25?

anonymous · Answer

No...

anonymous · Answer

What's 5^2?

anonymous · Answer

Are you there?

anonymous · Answer

Oh i forgot to square it. What a huge typo lol. The answer is actually $$5^2=2x^2\rightarrow x=3.536$$ Therefore the perimeter would be 4x=14.14 inches

anonymous · Answer

Thanks @qweqwe123123123123111

anonymous · Answer

NP, @4kec4 !

3.356 is more better...  :-)

anonymous · Answer

You hear that @adillie ? you should get 14.142 for your perimeter

anonymous · Answer

@qweqwe123123123123111 its getting late, maybe i should get some sleep seeing that i made that typo lol

anonymous · Answer

Heheh...

This error pales next to some of the doozies I've made on here!

anonymous · Answer

sorry internet connection was lost, 25

anonymous · Answer

Thank you both sorry I couldnt reply!

anonymous · Answer

no problem anytime