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Mathematics 18 Online
OpenStudy (anonymous):

-12x=72

OpenStudy (mathstudent55):

Divide both sides by -12.

OpenStudy (anonymous):

-12x=72/-12

OpenStudy (mathstudent55):

You have to do the same operation to both sides. Since to get rid of the -12 on the left side, you must divide by -12, you also divide the right side by -12. (-12x)/(-12) = 72/(-12)

OpenStudy (mathstudent55):

(-12x)/(-12) = x and 72/(-12) = -6, so the equation becomes x = -6

OpenStudy (anonymous):

So whatever you do on one side you have to do it to the other

OpenStudy (anonymous):

so if 10x+3=15 would be 10x/10 + 3= 15/10 +3

OpenStudy (thesecret20111):

Not quite it would be x+3=15/10 Then you would do x=(15/10)-3

OpenStudy (anonymous):

ok so I would divide 15 and 10 then subtract 3

OpenStudy (thesecret20111):

Yes

OpenStudy (thesecret20111):

So what you do when you have a simple equation like that is to try and get x by itself. You do this by doing the same to both sides whether that means subtracting, adding, multiplying or dividing.

OpenStudy (anonymous):

15/10-3=1.5 so x equals 1.5

OpenStudy (anonymous):

-1.5

OpenStudy (thesecret20111):

Yep

OpenStudy (anonymous):

Sweet

OpenStudy (anonymous):

3(5-y)=3(y+4) would be 15-3y=3y+7

OpenStudy (thesecret20111):

It would be 15-3y=3y+12

OpenStudy (mathstudent55):

@YesMe Yes, whatever operation you do to one side, you need to do to the other side. To solve the example you gave above, 10x+3=15 First, you must subtract 3 from both sides: 10x + 3 - 3 = 15 - 3 10x = 12 Then you divide both sides by 10: 10x/10 = 12/10 x = 6/5 = 1.2

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