Please need help. Find the center (h,k) and radius r of the circle and then use these to graph the circle. then find any intercepts if any.

4x^2+32x+y^2=0

Question

Please need help.  Find the center (h,k) and radius r of the circle and then use these to graph the circle. then find any intercepts if any.

4x^2+32x+y^2=0

anonymous · Answer

i think c(-8,0) and r=8

anonymous · Answer

thats what i thought as well but as i was looking at an example they had numbers that i had no idea where they came from.  how would i graph it?

raden · Answer

are u sure the equation given like above ?

4x^2+32x+y^2=0
it is not an equation of circle

anonymous · Answer

@ReadEn , it is it's (2x+8)^2 + (y+0)^2= 64 , 64 is r^2

raden · Answer

do u know the general formula the equation of circle, @kyusakazaki ?

anonymous · Answer

@RadEn yeah ,(x-a)^2 + (y-b)^2= r^2, c(a.b)

raden · Answer

obviously, the coefficient of x^2 and y^2 always be 1

we cant make the coeff of x^2 and y^2 be 1, right ?
4x^2+32x+y^2=0

raden · Answer

except, it is 4x^2+32x+4y^2=0 :)
@channie2003 , is there typo from u ?

anonymous · Answer

@RadEn so ?

raden · Answer

still wait confirm from asker, @channie2003 :)

anonymous · Answer

sorry let me double check im sure it is the right equation

anonymous · Answer

yeah the equation is exact

raden · Answer

therefore, the data is wrong :) this site might useful http://www.mathwarehouse.com/geometry/circle/equation-of-a-circle.php

anonymous · Answer

Thank you guys much :)

raden · Answer

you're welcome :)

anonymous · Answer

hey haw are you girl?

anonymous · Answer

I'm sorry mistake,sorry