Question

Can someone please help with these geometry questions? There's no graph or anything, just questions.

1. Write the equation of the mirror line for the segment with endpoints (5, 4) and (-1, -1).

2. Find the reflection of the point A(3, -2) through the mirror line of y = 1/2x − 1.

Answer 1

Please... I'm not asking for much..

Answer 2

well can you write the equation of the line between the endpoints given in problem 1.

Answer 3

What?

Answer 4

She said there is no graph so all we need to do here is get the slope-intercept equation

Answer 5

For number 1?

Answer 6

Yup I'm confident about it.....but what did you think we can do here?

Answer 7

I was looking at number 2 first because number 1 is really easy.

Answer 8

Lol I thought you're talking about #1. But ok let me work it out

Answer 9

Okay.

Answer 10

Oh this is simple all we have to look for first is a slope that is perpendicular to 1/2

Which is 2. So now we have to use the eq y-y1=m(x-x1)

We know m is 2 and y1 = -2 and x1 = 3

Answer 11

Plug in the given values into the equation. Can you solve for that @HallieBella?

Answer 12

What's y in y-y1=m(x-x1) ?
I see y1 = -2..

Answer 13

This will help you with #1 if you do not get it http://www.purplemath.com/modules/strtlneq.htm
If you get an answer for it, let us see and we'll see if you did right unless you know how to do this one already.

Answer 14

F(x)=y you are solving for the function y

Answer 15

I don't know..
I tried 2-(-2) = 4
then 2*(4-3) = 2
doesnt make sense.

Answer 16

?

Answer 17

Ok I'm going to show you the steps

Y-y1=m(x-x1)

Y-(-2)=-2(x-3)

Distribute the -2 to x and -3 and you get

Y+2=-2x+6

Subtract 2 on both sides and you get
Y=-2x+4

Answer 18

You understand

Answer 19

Oh okay. I'm sorry. Math isn't my strongest point... So what would that make #1??

Answer 20

ok so you know how to solve for the slope when you are given two coordinate points?

Answer 21

m is the slope so \[m=\frac{ (y2-y1) }{ (x2-x1) }=\frac{ (4+1) }{ (5+1) }=\frac{ 5 }{ 6 }\]

Answer 22

now use the equation used to solve for y

\[y-y1=m(x-x1)\]

and solve for y

Answer 23

so you get

\[y-(-1)=\frac{ 5 }{ 6 }(x-(-1))\]

then you have
\[y+1=\frac{ 5 }{ 6 }(x+1)\]

so you distribute the 5/6 and you get

\[y+1=\frac{ 5 }{ 6 }x+\frac{ 5 }{ 6 }\]

subtract 1 from both sides and you end up with

\[y=\frac{ 5 }{ 6 }x-\frac{ 1 }{ 6 }\]

your answer for the 1st question

Answer 24

Thank you so much♥

Answer 25

You welcome!!