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Mathematics 12 Online
OpenStudy (anonymous):

which is the simplified form of

OpenStudy (anonymous):

\[\frac{ 4x-12 }{ 3x-9 }\]

OpenStudy (anonymous):

factor a 4 in the numerator and a 3 in the denominator and you get \[\frac{4(x-3)}{3(x-3)}\] as a first step

OpenStudy (anonymous):

then cancel the common factor of \(x-3\) top and bottom

OpenStudy (anonymous):

\[\frac{ 4 }{ 3}\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

would it be a negitive

OpenStudy (anonymous):

no

OpenStudy (anonymous):

ok

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