By using substitution p=7^x
Show that 7^2x-4(7^x)+3=0 can be written as
P^2-4P+3=0
Solve the equation 7^2x-4(7^x)+3=0
Any help would be much appreciated

Question

By using substitution p=7^x
Show that 7^2x-4(7^x)+3=0 can be written as
P^2-4P+3=0
Solve the equation 7^2x-4(7^x)+3=0
Any help would be much appreciated

espex · Answer

Basically you just need to substitute 'p' anywhere you have 7^x, taking powers into account as well.

anonymous · Answer

Surely it can't be that easy? it has already been done on the question

espex · Answer

Based on the question, you will have to take the equation, substitute 'p', multiply it out (showing it can be written as:)$$P^{2}-4P+3=0$$ then solve for P. Once you know what p is you can answer the question $$P=7^{x}$$ at which point you can then solve the equation $$7^{2x}-4(7^{x})+3=0$$