Lim cotg2x/cotg5x X-->0
cotg means cot???
ah yes
convert it into tan and then use (tanx)/x=1 as x-->0
that would be tan5x/tan2x.now what? i mean there is not x.
Expand the denominator using double angle results.
Wait, actually don't do that. Try rationalising using tan2x/tan2x.
Bah, that doesn't work either. Where did you get this question from?
Wait, just change tan2x into (sin2x)(cos2x)
and then you get y=0
Try it out and tell me whether you get that.
(sin2x)/(cos2x)*
a book of mine.i was thinking about deviding both with an x.and then it would be like (tan2x/x and thhis devided by tan5x/x .and we know that tan2x/x is equal 2 and tan5x devided by x is 5 so it all equals 2/5 .what do u think?
Read what I wrote above.
Dang sorry, that doesn't work.
Sorry tan2x/x does not equal 2.
It's getting really late here, so I have to leave this with you. I'm sure someone else here will be glad to help you more than I did. Sorry about the inconvenience.
its ok,thanks anyway]
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