Question

no

Answer 1

@Luis_Rivera HELP or @amistre64 ? Can you help?

Answer 2

the rate of change of a linear function is just its slope

Answer 3

\[\lim_{h\to0}\frac{f(t+h)-f(t)}{h}\]
\[\lim_{h\to0}\frac{(-9-5(t+h))-(-9-5(t))}{h}\]
\[\lim_{h\to0}\frac{-9-5t-5h+9+5t}{h}\]
\[\lim_{h\to0}\frac{-5h}{h}=-5\]
at t=5, the rate of change is constantly -5

Answer 4

lol, and even at t=4 the rate is a constant -5

Answer 5

so thats the velocity?

Answer 6

yes

Answer 7

it is moving "backwards" at 5units per time