Question

which expression is a cube root of 2?
3sqrt2(cos(320) + isin(320))
3sqrt2(cos280)+isin(280))
3sqrt2(cos40)+isin(40))
3sqrt2(cos120)+isin(120))

Answer 1

Trying to use de moivre's theorem...[r(cosT + i*sinT)]^n = (r^n)(cos(nT) + i*sin(nT))

Answer 2

YEAH USE TO SOLVE BY DE MOIVER'S THEOREM
( COSX + iSINX)n = COSnX + i SINnX