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lim x→1 x^2-1/x+2
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is it not =0?
i got 0/3 but i don't know if that's right
@_Sam , please, explain us,
You got it iHeartYou, \[\lim_{x \rightarrow 1}\frac{(x-1)(x+1)}{x+2} \Longrightarrow \lim_{x \rightarrow 1}\frac{(1-1)(1+1)}{1+2} \\ \\ \Longrightarrow 0\]
@.Sam. is the answer 0 because 0/3 = 0
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Yes that's what you've got \[\lim_{x \rightarrow 1}\frac{(0)(2)}{3} \Longrightarrow \frac{0}{3}=0\]
thanks
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