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Algebra 14 Online
OpenStudy (anonymous):

Help please!!!!!!!

OpenStudy (anonymous):

Homework 96 the last problem!

OpenStudy (anonymous):

@Mertsj ?

OpenStudy (anonymous):

@bahrom7893

OpenStudy (anonymous):

I really need help like on the quick i have a paper left to do & omg its just really fustrating...

OpenStudy (tkhunny):

Too bad I won't open a "docx".

OpenStudy (anonymous):

I know...

OpenStudy (mertsj):

16) If the area of a circle is 144 cm^2 and the radius is x+4 , what is the value of x

OpenStudy (mertsj):

That problem?

OpenStudy (anonymous):

No # 13 is the homework 96

OpenStudy (mertsj):

13) 3m^2+30m+75=0

OpenStudy (mertsj):

Factor out the 3

OpenStudy (anonymous):

No the one with the squared is homework 96 not 95 it says it on the top

OpenStudy (mertsj):

Ok. I'm tired of guessing. How about YOU post YOUR problem.

OpenStudy (anonymous):

|dw:1367983827107:dw|

OpenStudy (anonymous):

What are the dimesions of the rectangle if the area is 100ft^2?

OpenStudy (anonymous):

Thats the problem.

OpenStudy (mertsj):

It says the area is 100. How do you find area of a rectangle?

OpenStudy (anonymous):

The dimensions though! not how to solve for area i know 10*10 = 100 but that wont make sense.

OpenStudy (mertsj):

How do you find the area of a rectangle?

OpenStudy (anonymous):

Multiplying i know that already.

OpenStudy (mertsj):

Multiplying what?

OpenStudy (anonymous):

anyways i plug in 25 for (x-15) & 10 for X

OpenStudy (anonymous):

& by width times lenght!

OpenStudy (mertsj):

The correct answer to "how do you find the area of a rectangle?" is "multiply the length by the width":

OpenStudy (mertsj):

What is the length of your rectangle?

OpenStudy (anonymous):

(x-15) & width is the X

OpenStudy (anonymous):

Or vice versa 0_o

OpenStudy (mertsj):

What do you get when you multiply them?

OpenStudy (anonymous):

x^2-15x

OpenStudy (mertsj):

What does the problem say that is equal to?

OpenStudy (anonymous):

its says the area of the rectangle is 100ft^2

OpenStudy (mertsj):

Write that equation.

OpenStudy (anonymous):

x^2-15x=100

OpenStudy (mertsj):

Subtract 100 from both sides.

OpenStudy (anonymous):

oh wait then you equal it to 0 so it would be x^2-15x-100=0

OpenStudy (mertsj):

Factor the left side: think of two numbers. their product is -100. their sum is -15

OpenStudy (anonymous):

20 & 5?

OpenStudy (anonymous):

-20 & 5!

OpenStudy (mertsj):

So what are the factors?

OpenStudy (anonymous):

wait idk if its + or -

OpenStudy (mertsj):

What is the sum of -20+5?

OpenStudy (anonymous):

-15 okay that makes sense now ^-^ after that do i set them equal to 0 again so it would become 20 & -5?

OpenStudy (mertsj):

Yes. And you would discard the -5. Why?

OpenStudy (anonymous):

because you can never have a negative there? & wait after would i plug in the 20 & just a+5 to the legnt and width?

OpenStudy (mertsj):

|dw:1367984590671:dw|

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